Reactionless Propulsion Device Video

testing file transfer 

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Aishwarya Rai was Sita (Vaidehi) in previous life

First little bit science. Read little bit background on my method  https://empyreanrelay.blogspot.com/2019/02/empyrean-theory.html?m=1   This theory gives us 2π×0.07179676972/0.00054461223777 = (2π+2) × 100  That gives π = 3.14159265....  0.07179676972 is geometric constant which is calculated by using Pythagorean theorem c^2 = a^2+b^2. This equation doesn't involve any value of Pi. If mass of proton is 1, then mass of electron is 0.00054461223777. If value of Pi is 3.14159265..., then mass of electron is 0.00054461223777. Proton/electron mass ratio is 1836.1688019. It's inevitable. 1836.1688019/5 = 367.23376. At the beginning, Earth's orbital period around Sun was 367.23376 days. I call it Empyrean year. Now Aishwarya Rai... Her birth date is 1.11.73 and on 15.4.70, there was Rama Navami.  From 15 April to 1 November, number of days = 200 200/367.23376 = 0.54461223777 There is another magic. If radius of inner circle is 0.1547005383792, then it compresses by (1+1/π)*100 to...
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Note - 13

God - Last words... Me  - That Triangle - Arrowhead solution to Newton's third law happened on borrowed money.  But society had given me those money on guarantee of my friends. Your rude mankind wasn't involved in this invention. And anyway I had repaid that society loan from my earned money. So this Triangle - Arrowhead invention belongs to me. Same thing about Triangle -Arrowhead Reactionless Propulsion. Because of your flawed economy,  governments keep printing money. Inflation keep rising. Prices of things keep rising. In my perfect economy,  I still would have left my earned money in my pocket. Hence instead of 3 thousand rupees,  I still would have left 1947 rupees in my pocket and in non-inflationary economy I still would have invented reactionless propulsion device on my earned money. You can't fool me by your flawed logic that these inventions have happened on public money. Also I discovered theory and equations on mobile which was bought on my friend's m...
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Aaditya Hridayam

[2×(c/e)×(1+1/π)]/10 = 0.1547005383792 c = e×(0.1547005383792×10)/[2×(1+1/π)]    = e×(0.1547005383792×5)/(1+1/π)   c  = 0.58673814101×e 9.15 am.  Oops ! Just noticed that 0.5867... × 2 = 1.17347628202 which is mass of electron. So c = (e/2) × e = e^2/2 So geometric speed of light = 0.00688523292
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